python

evodTuple =

print

tEvenCount = 0 tOddCount = 0

for i in range): # 检查当前元素是不是Neng被2整除 if evodTuple % 2 == 0: # Ru果Neng被2整除，是偶数，许多些偶数的计数 tEvenCount += 1 else: # 否则，是奇数，许多些奇数的计数 tOddCount += 1

print print