问题描述：

I need a regex for preg_match to accept all alphanumeric characters except l, L, v, V, 0, 2.

I\'ve tried

^[a-zA-Z0-9][^lLvV02]*$

It works good excluding lLvV02 but it also accept other characters like SPACE,ù,@,#, etc...

How should I change it?

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感谢您的意见，我们尽快改进~

功能建议

我需要preg_match的正则表达式接受除 l </ code>，之外的所有字母数字字符 L </ code>， v </ code>， V </ code>， 0 </ code>， 2 </ code>。</ p>

我试过</ p>

  ^ [a-zA-Z0-9] [^ lLvV02] * $ 
</ code> </ pre> 
\\  n 
排除lLvV02后效果很好，但它也接受SPACE，ù，@，＃等其他字符...... </ p> 
我该如何更改？</ p> \\  n </ div> 
网友观点：
You may use
^(?:(?![lLvV02])[a-zA-Z0-9])*$
Details
^ - start of string
(?: - start of a non-capturing group
(?![lLvV02])[a-zA-Z0-9] - an alnum char that is not one of the chars inside the character class residing inside a negative lookahead
)* - end of the non-capturing group, 0 or more repetitions
$ - end of string
See the Regulex graph:
    
I know you asked for a Regex, but you can test for alphanumeric first and only if that passes check that the others are NOT present:
if(ctype_alnum($string) && !preg_match(\'/[lLvV02]/\', $string)) {
//pass
} else {
//fail
}
Or possibly substitute preg_match(\'/^[^lLvV02]+$/\', $string).
    
Easiest would probably be: ^[a-km-uw-zA-KM-UW-Z13-9]*$.
I\'m not saying that it\'s pretty but it does what it\'s supposed to.
    
正则表达式匹配
描述
给你一个字符串 s 和一个字符规律 p，请你来实现一个支持 '.' 和 '*' 的正则表达式匹配。
'.' 匹配任意单个字符
'*' 匹配零个或多个前面的那一个元素
所谓匹配，是要涵盖整个字符串 s的，而不是部分字符串。