问题描述：

I search for patterns like this number+space+number+space+anything

If have this right now:

if( preg_match( \'[0-9][ ][0-9][ ].\', $searchString ) )

This seems to work ok but fails on the numbers. As far as i can see there should be a selector for \"any number\". How can i do this in regex.

It should return true for these cases:

0 0 asdf
1 0 asdf
0 30 adsf asdf
22 0 a
...

图片转代码服务由CSDN问答提供

感谢您的意见，我们尽快改进~

功能建议

我搜索这样的模式+空格+数字+空格+任何东西</ p>

<n p>如果现在有这个：</ p>

  if（preg_match（\'[0-9] [] [0-9] []。\'，$ searchString））
</ code> </ pre> 
这似乎工作正常，但数字失败。 据我所知，应该有一个“任意数字”的选择器。 如何在正则表达式中执行此操作。</ p> 
对于这些情况，它应该返回true：</ p> 
  0 0 asdf 
1 0 asdf 
0  30 adsf asdf 
22 0 a 
... 
</ code> </ pre> 
</ div> 
网友观点：
[0-9] only accepts the integers 0,1,2,3,4,5,6,7,8,9. For any integer, you need to allow one or more repetitions of [0-9]. If you use the shortcut \\d for [0-9] then you can write it as
\\d+ \\d+ .*
The + symbol means One or more repetitions.
Note: 
It seems like your new to reg expression. Try out this free regex tutorial.
    
I\'m kind of surprised that works seeing that you should have your regex between //. But that aside, you should realise that your [0-9] is only looking for a MANDATORY ONE INSTANCE of a digit.
Changing that to [0-9]+ should fix your issue, though I think studying a bit of regex first will help you in the long run.
    
Change your regexp pattern as shown below:
$re = \\\"/\\d+? \\d+? .*$/\\\";
var_dump(preg_match($re, \\\"0 30 adsf asdf\\\"));  // 1
var_dump(preg_match($re, \\\"22 0 a\\\"));          // 1
Details:
\\d+? - should match at least one number
.*$  - matches any character at the end of the string
PHP正则表达式核心技术完全详解 第7节 数组元素正则匹配
作者：极客小俊  一个专注于web技术的80后
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博客: 极客小俊GeekerJun
PHP正则匹配数组中的元素
preg_grep(参数..)  返回匹配模式的数组条目,数组中符合正则表达式条件的数组元素 ,并且返回数据类型是数组! 参数列表: 参数1:正则表达式 参数2:检测匹配的数组  索引数组 关联数组 都是可以的! 参数3: 设置结果为正则不匹配的元素组成的数组
案例代码1: