MySQL多表查詢的語句多表連接查詢

# 創建表 create table department(id int,name varchar(20)); create table employee1( id int primary key auto_increment, name varchar(20), sex enum('male','female') not null default 'male', age int, dep_id int ); # 插入數據 insert into department values(200,'技術'),(201,'人力資源'),(202,'銷售'),(203,'運營');  insert into employee1(name,sex,age,dep_id) values('egon','male',18,200),('alex','female',48,201),('tom','male',38,201),('yuanhao','female',28,202),('lidawei','male',18,200),('jinkezhou','female',18,204);  # 查看錶 mysql&gt; select * from employee1; +----+-----------+--------+------+--------+ | id | name      | sex    | age  | dep_id | +----+-----------+--------+------+--------+ |  1 | egon      | male   |   18 |    200 | |  2 | alex      | female |   48 |    201 | |  3 | tom       | male   |   38 |    201 | |  4 | yuanhao   | female |   28 |    202 | |  5 | lidawei   | male   |   18 |    200 | |  6 | jinkezhou | female |   18 |    204 | +----+-----------+--------+------+--------+ 6 rows in set (0.00 sec) mysql&gt; select * from department; +------+--------------+ | id   | name         | +------+--------------+ |  200 | 技術       | |  201 | 人力資源   | |  202 | 銷售       | |  203 | 運營       | +------+--------------+ 4 rows in set (0.00 sec)

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# 創建表 create table department(id int,name varchar(20)); create table employee1( id int primary key auto_increment, name varchar(20), sex enum('male','female') not null default 'male', age int, dep_id int ); # 插入數據 insert into department values(200,'技術'),(201,'人力資源'),(202,'銷售'),(203,'運營'); insert into employee1(name,sex,age,dep_id) values('egon','male',18,200),('alex','female',48,201),('tom','male',38,201),('yuanhao','female',28,202),('lidawei','male',18,200),('jinkezhou','female',18,204); # 查看錶 mysql> select * from employee1; +----+-----------+--------+------+--------+ | id | name | sex | age | dep_id | +----+-----------+--------+------+--------+ | 1 | egon | male | 18 | 200 | | 2 | alex | female | 48 | 201 | | 3 | tom | male | 38 | 201 | | 4 | yuanhao | female | 28 | 202 | | 5 | lidawei | male | 18 | 200 | | 6 | jinkezhou | female | 18 | 204 | +----+-----------+--------+------+--------+ 6 rows in set (0.00 sec) mysql> select * from department; +------+--------------+ | id | name | +------+--------------+ | 200 | 技術 | | 201 | 人力資源 | | 202 | 銷售 | | 203 | 運營 | +------+--------------+ 4 rows in set (0.00 sec)

mysql&gt; select * from employee1 ,department;

1	mysql> select * from employee1 ,department;

# 找兩張表共有的部分，相當於利用條件從笛卡爾積結果中篩選出了正確的結果 #department沒有204這個部門，因而employee表中關於204這條員工信息沒有匹配出來 mysql&gt; select * from employee1,department where employee1.dep_id=department.id;  #上面用where表示的可以用下面的內連接表示，建議使用下面的那種方法 mysql&gt; select * from employee1 inner join department on employee1.dep_id=department.id;  # 也可以這樣表示哈 mysql&gt; select employee1.id,employee1.name,employee1.age,employee1.sex,department.name from employee1,department where employee1.dep_id=department.id;

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# 找兩張表共有的部分，相當於利用條件從笛卡爾積結果中篩選出了正確的結果 #department沒有204這個部門，因而employee表中關於204這條員工信息沒有匹配出來 mysql> select * from employee1,department where employee1.dep_id=department.id; #上面用where表示的可以用下面的內連接表示，建議使用下面的那種方法 mysql> select * from employee1 inner join department on employee1.dep_id=department.id; # 也可以這樣表示哈 mysql> select employee1.id,employee1.name,employee1.age,employee1.sex,department.name from employee1,department where employee1.dep_id=department.id;

#左鏈接：在按照on的條件取到兩張表共同部分的基礎上，保留左表的記錄 mysql&gt; select * from employee1 left join department on department.id=employee1.dep_id;  mysql&gt; select * from department left join  employee1 on department.id=employee1.dep_id;

1	#左鏈接：在按照on的條件取到兩張表共同部分的基礎上，保留左表的記錄 mysql> select * from employee1 left join department on department.id=employee1.dep_id; mysql> select * from department left join employee1 on department.id=employee1.dep_id;

#右鏈接：在按照on的條件取到兩張表共同部分的基礎上，保留右表的記錄 mysql&gt; select * from employee1 right join department on department.id=employee1.dep_id; mysql&gt; select * from department right join employee1 on department.id=employee1.dep_id;

1	#右鏈接：在按照on的條件取到兩張表共同部分的基礎上，保留右表的記錄 mysql> select * from employee1 right join department on department.id=employee1.dep_id; mysql> select * from department right join employee1 on department.id=employee1.dep_id;

mysql&gt; select * from department full join employee1;

1	mysql> select * from department full join employee1;

mysql&gt; select * from employee1 inner join department on employee1.dep_id=department.id and age&gt;25;

1	mysql> select * from employee1 inner join department on employee1.dep_id=department.id and age>25;

mysql&gt; select * from employee1 inner join department on employee1.dep_id=department.id and age&gt;25 and age&gt;25 order by age asc;

1	mysql> select * from employee1 inner join department on employee1.dep_id=department.id and age>25 and age>25 order by age asc;

#1：子查詢是將一個查詢語句嵌套在另一個查詢語句中。 #2：內層查詢語句的查詢結果，可以為外層查詢語句提供查詢條件。 #3：子查詢中可以包含：IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等關鍵字 #4：還可以包含比較運算符：= 、 !=、&gt; 、&lt;等</code><code class="null">

1 2	#1：子查詢是將一個查詢語句嵌套在另一個查詢語句中。 #2：內層查詢語句的查詢結果，可以為外層查詢語句提供查詢條件。 #3：子查詢中可以包含：IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等關鍵字 #4：還可以包含比較運算符：= 、 !=、> 、<等</code><code class="null">

# 查詢平均年齡在25歲以上的部門名 mysql&gt; select name from department where id in ( select dep_id from employee1 group by dep_id having avg(age) &gt; 25 );  # 查看技術部員工姓名 mysql&gt; select name from employee1 where dep_id = (select id from department where name='技術');  # 查看小於2人的部門名 mysql&gt; select name from department where id in (select dep_id from employee1 group by dep_id having count(id) &lt; 2) union select name from department where id not in (select distinct dep_id from employee1); # 提取空部門                               #有人的部門 mysql&gt; select * from department where id not in (select distinct dep_id from employee1);

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# 查詢平均年齡在25歲以上的部門名 mysql> select name from department where id in ( select dep_id from employee1 group by dep_id having avg(age) > 25 ); # 查看技術部員工姓名 mysql> select name from employee1 where dep_id = (select id from department where name='技術'); # 查看小於2人的部門名 mysql> select name from department where id in (select dep_id from employee1 group by dep_id having count(id) < 2) union select name from department where id not in (select distinct dep_id from employee1); # 提取空部門 #有人的部門 mysql> select * from department where id not in (select distinct dep_id from employee1);